Problem

A Pointer in C++ is used to share a memory address among different contexts (primarily functions).

They are used whenever a function needs to modify the content of a variable, but it does not have ownership.

In order to access the memory address of a variable, *val*, prepend it with *&* sign.

For example, &val returns the memory address of *val*.

This memory address is assigned to a pointer and can be shared among functions.

For example, *int*p = &val* assigns the memory address of *val* to pointer p.

To access the content of the memory pointed to, prepend the variable name with a *.

For example, *p will return the value stored in *val* and any modification to it will be performed on *val*.

void increment (int *v) {
   (*v)++;
}

int main() {
    int a;
    scanf("%d", &a);
    increment(&a);
    printf("%d", a);
    return 0;
}

Function Description

Complete the update function in the editor below.

update has the following parameters:

• int*a: an integer
• int*b: an integer

Returns

The function is declared with a void return type,so there is no value to return.

Modify the values in memory so that *a* contains their sum and *b* contains their absoluted difference.

• a’ = a + b
• b’ = |a - b|

Input Format

Input will contain two integers, *a* and *b*, separated by a newline.

Sample Input

4
5

Sample Output

9
1

Explanation

a’ = 4 + 5 = 9

b’ = | 4 - 5 | = 1

Solution - Pointer in C++

#include <stdio.h>

void update(int *a,int *b) {
    // Complete this function 
    int temp = *a;   
    *a = *a + *b;
    *b = temp - *b;
    
    if (*b < 0)
    {
        *b = -(*b);
    }
}

int main() {
    int a, b;
    int *pa = &a, *pb = &b;
    
    scanf("%d %d", &a, &b);
    update(pa, pb);
    printf("%d\n%d", a, b);

    return 0;
}